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Magic Cubic (Posted on 2005-11-28) Difficulty: 2 of 5
Number the corners of a cube from 1 to 8, so that the sum of the four corners of every face is the same.

No Solution Yet Submitted by sragen    
Rating: 2.6667 (6 votes)

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Solution? | Comment 7 of 14 |

If facing the cube from the front, and the back four are in a group, and the front four are a group, then the number are as follows (in their respective order):

back: 67
         32

front: 14
         85

the faces' numbers would then be: {6,3,1,8}, {7,2,4,5}, {6,7,4,1}, {3,2,5,8}, {6,7,2,3}, and {1,4,5,8}.

This one took me a few minutes. :)


  Posted by darkinflection on 2005-12-02 20:48:07
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