Counting digits (Posted on 2003-02-20)

	Submitted by Anoop
Rating: 3.8750 (8 votes)
Solution:	(Hide)
Ender has provided the solution in the comments list Anyway, 2^1000 = 10^(1000*log2) = 10^(301.03) So you can round the exponent to 301. So including the 1 and the 301 zeroes, the answer is 302 digits.

	Subject	Author	Date
	Answer	Praneeth	2007-08-24 01:47:16
	Puzzle Solution With Explqanation	K Sengupta	2007-05-13 12:40:13
	answer	K Sengupta	2007-05-13 12:35:14
	re(3): And they are...	Charlie	2003-03-09 07:21:05
	re(2): And they are...	Gamer	2003-03-08 15:17:25
	try to use log	Alex	2003-03-05 04:40:16
	re: check this out (where did it go wrong?)	Charlie	2003-03-02 10:52:57
	check this out	akila	2003-03-01 17:06:42
	re(2): And they are...	Charlie	2003-02-26 08:20:19
	re: And they are...	Ravi Raja	2003-02-26 04:48:14
	re: yay	Ravi Raja	2003-02-26 04:46:01
	And they are...	Charlie	2003-02-25 18:42:33
	yay	Irina	2003-02-25 12:12:36
	yay	Irina	2003-02-25 12:11:57
	re(2): another guess	Jana	2003-02-21 08:33:12
	re: another guess	TomM	2003-02-20 16:10:21
	another guess	Jana	2003-02-20 13:07:09
	Simple concept	Alan	2003-02-20 12:29:39
	re(2): Solution	TomM	2003-02-20 11:10:49
	re: Solution	levik	2003-02-20 11:03:13
	Solution	gary	2003-02-20 09:43:18
	Scientific guess	Ender	2003-02-20 04:07:32
	Unscientific guess	fwaff	2003-02-20 03:28:44
	I kind of cheated	Nick Murray	2003-02-20 02:56:39