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Stupid number trick (Posted on 2005-12-01) Difficulty: 1 of 5
Take any three different digits.

1. Create every possible two-digit combination.
2. Find their sum.
3. Sum the original three digits.
4. Divide your answer from part 2 by your answer to part 3.

What number do you always get, and why?

See The Solution Submitted by Jer    
Rating: 2.3333 (6 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution | Comment 2 of 9 |

Take 3 different digits a, b, and c.

Then all combinations are: ab, ac, ba, bc, ca, and cb

Thus the sum is :

10a + b + 10a +c + 10b + a + 10 b + c + 10c + a + 10c + b

or 22a + 22b + 22c

Thus we have 22(a + b + c) / (a + b + c) = 22


  Posted by Walter on 2005-12-01 09:02:02
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