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Cubic Problem: Existence Of A Solution (Posted on 2005-12-28) Difficulty: 3 of 5
Does there exist any positive integral solution of the equation given below?

16(X³+Y³) + 12(X²+Y²) + 3(X+Y) = 2,138,156,388

See The Solution Submitted by K Sengupta    
Rating: 3.0000 (2 votes)

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re: small problem | Comment 3 of 8 |
(In reply to Solution! by Eric)

Small problem:

If f (x,y) =16(x^3+y^3)+12(x^2+y^2)+3(x+y), then

f (9439,-9439) = f (9439,-9439) = 2,138,273,304

not 2,138,156,388 as required.

In your solution

Solving 24 x^2 = 2,138,156,388 gives (plus/minus)

Sqrt[178179699/2] = 9438.74.. not 9439.


  Posted by goFish on 2005-12-28 20:24:34
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