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 Stupid number trick II (Posted on 2006-01-02)
Take any whole number (larger numbers are more interesting)

1. x=the number of even digits, y=the number of odd digits, z=the total number digits.
2. Concatenate to create the number xyz (a leading zero is ok if x=0)

[Example: 12345678901 has x=5, y=6, z=11 for step 1 and 5611 for step 2]

3. Repeat steps 1 and 2 of this process until your number is unchanged.

What number(s) will the process terminate at?
Will the process always terminate?
Find a 20 digit starting number that terminates in the maximum number of steps (among 20 digit numbers.)

 See The Solution Submitted by Jer Rating: 3.6667 (3 votes)

 Subject Author Date Answer K Sengupta 2008-03-19 11:20:38 Answer Praneeth 2007-09-11 03:03:55 re(2): Maximum termination- try this Gamer 2006-01-02 20:00:41 re: Maximum termination- try this goFish 2006-01-02 18:33:54 Spoiler: Maximum termination Steve Herman 2006-01-02 18:25:08 some solutions (I think) Hugo 2006-01-02 16:48:02

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