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Stupid number trick II (Posted on 2006-01-02) Difficulty: 2 of 5
Take any whole number (larger numbers are more interesting)

1. x=the number of even digits, y=the number of odd digits, z=the total number digits.
2. Concatenate to create the number xyz (a leading zero is ok if x=0)

[Example: 12345678901 has x=5, y=6, z=11 for step 1 and 5611 for step 2]

3. Repeat steps 1 and 2 of this process until your number is unchanged.

What number(s) will the process terminate at?
Will the process always terminate?
Find a 20 digit starting number that terminates in the maximum number of steps (among 20 digit numbers.)

See The Solution Submitted by Jer    
Rating: 3.6667 (3 votes)

Comments: ( You must be logged in to post comments.)
  Subject Author Date
AnswerK Sengupta2008-03-19 11:20:38
AnswerPraneeth2007-09-11 03:03:55
re(2): Maximum termination- try thisGamer2006-01-02 20:00:41
re: Maximum termination- try thisgoFish2006-01-02 18:33:54
Spoiler: Maximum terminationSteve Herman2006-01-02 18:25:08
some solutions (I think)Hugo2006-01-02 16:48:02
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