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 Two squares (Posted on 2006-01-05)
Construct a large square ABCD with AB at the top.

Next construct a smaller square (A'B'C'D') inside ABCD, with any orientation and centre and join the corresponding corners.

This divides the region between the squares into four.

We will name these divisions (and their areas):

(N)orth = ABB'A'
(E)ast = BCC'B'
(S)outh = CDD'C'
(W)est = DAA'D'.

Show that the areas of these regions satisfy the equality
N+S = E+W.

 See The Solution Submitted by goFish Rating: 4.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(4): Solution | Comment 6 of 7 |
(In reply to re(3): Solution by Ken Haley)

` `
`In your example (with both ABCD and A'B'C'D' labeled CCW,AB parallel to A'B', and both AB and A'B' at the top):`
`Using the complex cross product, the area of the Northregion is negative and the area of the East, West, andSouth regions are positive. So that N+S = E+W.`
`Note: In my Solution post change every place you see "2i*"      to "4i*".`
` `

 Posted by Bractals on 2006-01-07 12:13:32

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