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 Stupid number trick IV (Posted on 2006-01-13)
Take any whole number greater than one.

1. If the number is odd, multiply it by three and add one.
2. If it is even divide it by two.
2a. If the result is still even, continue to divide by two until the result is odd.
3. Continue steps 1 and 2 until you get the same number twice.

[For example starting with 9 -> 28 -> 14 -> 7 which is considered one iteration. The next iteration brings this to 11.]

What number(s) does this process terminate at?
What starting value less than 200 takes the most iterations to terminate?

 See The Solution Submitted by Jer Rating: 4.0000 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Answer | Comment 6 of 23 |
And the brute force program found the number to be 171. (45 iterations)
 Posted by Joe on 2006-01-13 20:18:47
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