All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
The Descending Integers (Posted on 2006-02-02) Difficulty: 3 of 5
Let us consider all possible positive whole numbers (not containing any leading zeroes) with the proviso that in each of the numbers, none of its digits can be repeated.

Note: any given number may or may not contain all the digits from 0 to 9 (Examples: 7; 20; 1056; 3067941825 etc.)

These numbers are now arranged in descending order of magnitude.

What would be the 200,136th number?

See The Solution Submitted by K Sengupta    
Rating: 2.8000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Acknowledgements Comment 8 of 8 |

Due acknowledgements are in order to:<o:p></o:p>

Charlie , for his speedy response in solving the problem by an analytic method and subsequent computer verification.<o:p></o:p>

goFish, for providing a  detailed method for solving the problem .<o:p></o:p>

Bill Matthews, for accurately solving the problem in his first post.
  Posted by K Sengupta on 2006-03-15 01:13:34
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (10)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information