A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.
(In reply to Solution
The isosceles right triangle with hypotenuse 6 will clearly have QA²=QB²=10. 10+10=36×5/9, so our value of 5/9 checks out.
Posted by Richard
on 2006-02-03 18:55:52