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Trisected Triangle (Posted on 2006-02-03) Difficulty: 3 of 5
A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.

No Solution Yet Submitted by Chris, PhD    
Rating: 4.5000 (4 votes)

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re: Solution | Comment 4 of 12 |
(In reply to Solution by Justin)

The isosceles right triangle with hypotenuse 6 will clearly have QA²=QB²=10. 10+10=36×5/9, so our value of 5/9 checks out.
  Posted by Richard on 2006-02-03 18:55:52

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