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Trisected Triangle (Posted on 2006-02-03) Difficulty: 3 of 5
A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.

No Solution Yet Submitted by Chris, PhD    
Rating: 4.5000 (4 votes)

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re(3): Solution | Comment 6 of 12 |
(In reply to re(2): Solution by Justin)

By using exp(it), my solution is no longer elementary, however, and unlike yours, may not be understood by high school students. However, by replacing exp(it) by cos(t) +isin(t), my solution can at least be made as elementary as high school trig, and maybe I should have done that instead.  Anyway, we got the same answer, which is clearly the correct one.
  Posted by Richard on 2006-02-03 22:15:48

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