A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.
(In reply to
re(2): Solution by Justin)
By using exp(it), my solution is no longer elementary, however, and
unlike yours, may not be understood by high school students. However,
by replacing exp(it) by cos(t) +isin(t), my solution can at least be
made as elementary as high school trig, and maybe I should have done
that instead. Anyway, we got the same answer, which is clearly
the correct one.
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Posted by Richard
on 2006-02-03 22:15:48 |
re(3): Solution
