A right triangle PQR, has its hypotenuse, PR, trisected at points A and B. Two lines, QA and QB are then drawn and k is such that QA^2 + QB^2 = (PR^2) * k. Find the value of k.
(In reply to re(3): Solution
I prefer mine, not because it is better, but because I've forgotten my CIS stuff from trig. That was a sophomore class, and now I'm in my 2nd AP Calc class, so as you can imagine, somethings are lost in the process, and CIS was one of them. But, like you said, we both got the same answer, which is "clearly the correct one"
Posted by Justin
on 2006-02-03 22:20:33