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Harmonic Integers (Posted on 2006-02-07) Difficulty: 3 of 5
Given that, a, b, and c are all positive integers so that a < b < c, and 1/a, 1/b, and 1/c are in arithmetic progression, can a² + b² be equal to c²?

See The Solution Submitted by K Sengupta    
Rating: 2.2000 (5 votes)

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re: I think I have it | Comment 2 of 5 |
(In reply to I think I have it by Mindrod)

Maybe you meant to set 1/b + k = 1/c and 1/a +2k = 1/c. Also, I don't think k has to be an integer, it just has to be rational.

 


  Posted by Eric on 2006-02-08 03:19:25
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