In a triangle ABC, D is the midpoint of BC. Join AD. Angle ADB = 45 degree and angle ACB = 30 degree. Find angle ABC.
ABC and DBA are similar, and proving that will give a solution because
angle ACB is 30 and angle ADB is 45, so angle ABC must be 105.
The only problem is proving that ABC and DBA are similar, then. I still
don't see how to do this, but it should be possible, and perhaps
possible without using trig.
Posted by Richard
on 2006-02-25 18:08:42