All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Algorithms
Wolf in a field (Posted on 2006-02-23) Difficulty: 3 of 5
There is a wolf in the centre of a square field, and four dogs in the corners. The wolf can easily kill one dog, but two dogs can kill the wolf. The wolf can run all over the field, and the dogs -- along the fence (border) only. Prove that if a dog's speed is 1.5 times more than the wolf's, then the dogs can prevent the wolf escaping.

No Solution Yet Submitted by goFish    
Rating: 3.0000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
solution | Comment 12 of 17 |

The only possible way wolf can escape is to lure two dogs at the centre of a side and run to a point farthest away from two adjacent dogs.

Lets say if the sides of square is of unit size then the maximum distance that he can create between two dogs would be 1.5

The distance he needs to travel is 0.5 to reach the edge. Hence the speed of the dog should be maximum 1.5/.5/2 times the speed of the wolf. i.e. 1.5 times.

 


  Posted by salil on 2006-02-24 10:18:17
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (10)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information