Fill in the boxes using each digit from 1 to 9 once so that each equation is correct. Note that all operations are performed in order from left to right or top to bottom.
_ _ _
_ x _  _ = 6
+ + +
_ _ _
_ + _  _ = 5
 x /
_ _ _
_ x _ / _ = 3
= = =
2 9 4
(In reply to
thinkigotit by Wallace North)
Yep, that's what I got too. I won't go through the whole process, but here's a start...
Label the 9 missing digits as:
A B C
D E F
G H I
A good place to start is with H. You know that (B+E)*H = 9, so H must be either 3 or 1. If H was 3, then G and I would have to be the same number, which is not allowed. Therefore, H is 1.
Going across, G*1/I = 3, so either G=6 and I=2, or G=9 and I=3. If I=2, then C+F would have to equal 8. But this would mean that C & F were 5 & 3 (in some order). A quick inspection shows that this is impossible (try plugging 3 for C or F and solve the row, it's impossible). Therefore, G=9 and I=3.
Etc.

Posted by tomarken
on 20060328 10:42:00 