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How Many Pairs (Posted on 2006-03-14) Difficulty: 2 of 5
The sum of two positive numbers is 1068 and their Highest Common Factor is 89. How many pairs of such numbers are there?

No Solution Yet Submitted by Ravi Raja    
Rating: 2.5000 (6 votes)

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Solution: 5 pairs | Comment 5 of 13 |

A+B = 1068 = 89*a + 89*b = 89*(a+b) 

a+b = 1068/89 = 12

And there are five such pairs of positive numbers that add up to 12:
1, 11
2, 10
3, 9
4, 8
5, 7


  Posted by Dej Mar on 2006-03-14 18:58:44
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