The number of terms of an Arithmetic Progression is even.
The sum of the terms in the odd places (First term + Third Term + Fifth Term + ...and so on) is 24;
The sum of the terms in the even places (Second Term + Fourth Term + Sixth Term + ... and so on) is 30; and
The last term exceeds the first by 21/2, then:
What is the arithmetic progression?
The number of terms is given to be even. However, that did not
need to be required  it can be proved form the other
specifications. If the terms are a, a+d, ..., a+2nd then the odd
places sum to (n+1)(a+nd)=24 and the even places sum to n(a+nd)=30 so
that (n+1)/n=24/30 which is impossible.

Posted by Richard
on 20060323 13:25:20 