Lets begin with 1 quart = 1 quart.
The equation for the area of a circle, c, is c = 2πr2,
thus r = √(c/2π). We can, therefore, restate the equation as:
1 quart = 1 qua(√c/2π)t
On the complex plane, §Ù, if we appy the Guinness factor to the circle, we get a hyperbolic curve. We can then apply the Coor's Corollary and divide the first coefficient to the hypertangent, n¥ø, and substitute this in the equation for a. We now have:
1 quart = 1 qu n¥ø (√(c/2π)t
Now taking the Heineken derivative for ∆q/t and multiplying by the Pilsner constant (ps) we rewrite the equation:
1 quart = (√(c/2π))^{2})u)/(1/8π(ps))
Simplifying we get:
1 quart = 4 (c)(u)(ps)
And we know 4 (c)(u)(ps) = 2 pi(n)(t)(s)
Edited on April 4, 2006, 4:23 am

Posted by Dej Mar
on 20060404 00:25:30 