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 That's a lotta numbers! (Posted on 2006-04-14)
Consider all nine-digit numbers consisting of one each of the digits 1 through 9.

What is the sum of these numbers?

 Submitted by Jer Rating: 3.2500 (4 votes) Solution: (Hide) Each number appears in each position 8! times. 1+2+...+9=45 so the solution is 45*111111111*8!= 201599999798400

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 Subject Author Date That's a lotta numbers hugh 2006-04-19 00:06:14 I think Tim 2006-04-17 01:14:25 re: Another Viewpoint K Sengupta 2006-04-15 20:38:06 A solution Dej Mar 2006-04-15 06:14:30 Another Viewpoint Richard 2006-04-14 15:57:23 re: Is this it? -- computer verification Charlie 2006-04-14 15:03:32 Generalised Result: Detailed Solution Not Given K Sengupta 2006-04-14 12:28:12 The Solution K Sengupta 2006-04-14 12:19:36 Is this it? tomarken 2006-04-14 11:49:48 Some Hints For Solving The Problem K Sengupta 2006-04-14 09:45:40
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