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That's a lotta numbers! (
Posted on 20060414
)
Consider all ninedigit numbers consisting of one each of the digits 1 through 9.
What is the sum of these numbers?
Submitted by
Jer
Rating:
3.2500
(4 votes)
Solution:
(
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Each number appears in each position 8! times. 1+2+...+9=45 so the solution is 45*111111111*8!= 201599999798400
Comments: (
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Subject
Author
Date
That's a lotta numbers
hugh
20060419 00:06:14
I think
Tim
20060417 01:14:25
re: Another Viewpoint
K Sengupta
20060415 20:38:06
A solution
Dej Mar
20060415 06:14:30
Another Viewpoint
Richard
20060414 15:57:23
re: Is this it?  computer verification
Charlie
20060414 15:03:32
Generalised Result: Detailed Solution Not Given
K Sengupta
20060414 12:28:12
The Solution
K Sengupta
20060414 12:19:36
Is this it?
tomarken
20060414 11:49:48
Some Hints For Solving The Problem
K Sengupta
20060414 09:45:40
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