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Integer Solutions (Posted on 2006-03-30) Difficulty: 3 of 5
Determine all integer solutions (x,y,z) for the system of equations

x²z + y²z + 4xy = 40,

x² + y² + xyz = 20

See The Solution Submitted by Bractals    
Rating: 2.5000 (6 votes)

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Answer, without detailed explanation | Comment 5 of 16 |


The above posts were certainly enlightening.  I had convinced myself that I had found an infinite number of solutions to this problem, but only after looking at what others had posted did I realize my error.  So, almost all of my "solutions" had to be discarded, as they actually didn't satisfy the original equations.  However, I did end up with 4 possible solution triples.  Two of them have been mentioned previously, namely

(1,1,18) and (-1,-1,18).

There is another pair of solutions though!  If you are keen to try and find them on your own, then don't read any further, as I will give them away below.







The other pair is (2,2,3) and (-2,-2,3).  As far as I could tell in my calculations I exhausted all other possibilities.  So I believe that these are the only 4 answers.  It will certainly be interesting to see any more correspondence on this problem!  Thanks to Bractals for the great puzzle.


  Posted by John Reid on 2006-03-30 16:11:14
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