Find three positive rational numbers such that their sum is a square, and the sum of any pair exceeds the third by a square.

Classical Rules: Let a "square" be any number that is the square of a rational number.

64, 40, 40

The sum of the three positive rational numbers is a square:
64 + 40 + 40 = 12²

And any two pair of the numbers exceed the third number by a square:
(64 + 40) - 40 = 8²
(40 + 40) - 64 = 4²

Edited on April 18, 2006, 5:56 am

Posted by Dej Mar on 2006-04-18 05:37:24