Find three positive rational numbers such that their sum is a square, and the sum of any pair exceeds the third by a square.
Classical Rules: Let a "square" be any number that is the square of a rational number.
64, 40, 40
The sum of the three positive rational numbers is a square:
64 + 40 + 40 = 12^{2}
And any two pair of the numbers exceed the third number by a square:
(64 + 40)  40 = 8^{2}
(40 + 40)  64 = 4^{2}
Edited on April 18, 2006, 5:56 am

Posted by Dej Mar
on 20060418 05:37:24 