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ABCDEABCDE is one (Posted on 2006-05-17) Difficulty: 2 of 5
How many arrangements of the letters AABBCCDDEE are there such that there are no double letters in the sequence?

See The Solution Submitted by Jer    
Rating: 4.5000 (2 votes)

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Some Thoughts Solution (?) | Comment 1 of 4

I am not positive, but would this not be...

10!/2!2!2!2!2!-(5*9!/2!2!2!2!-4*(8!/2!2!2!-3*(7!/2!2!-2*(6!/2!))))

= 68400 arrangements


  Posted by Dej Mar on 2006-05-17 10:06:49
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