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 Three from Nine (Posted on 2006-04-25)
Nine marbles numbered 1 to 9 are placed in a barrel and three are drawn out, without replacement. Determine -:

1. The probability that the three digit number formed from the marbles in the order drawn is divisible by (a) Five (b) Seven (c) Nine.
2. The probability that a three digit number can be formed by rearranging the marbles drawn, that is divisible by (a) Five (b) Seven (c) Nine.

 No Solution Yet Submitted by Vernon Lewis Rating: 3.5000 (4 votes)

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 re(2): Partial Solution | Comment 4 of 12 |
(In reply to re: Partial Solution by Jer)

Yeah, I just caught that and was about to correct myself. :)  It looks like you have the right idea.

As far as the divisibility by 7, I also think that it would be 1/7 and 6/7, respectively, but I'm not sure how to show that it is...

 Posted by tomarken on 2006-04-25 13:16:20

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