Nine marbles numbered 1 to 9 are placed in a barrel and three are drawn out, without replacement. Determine -:
1. The probability that the three digit number formed from the marbles in the order drawn is divisible by (a) Five (b) Seven (c) Nine.
2. The probability that a three digit number can be formed by rearranging the marbles drawn, that is divisible by (a) Five (b) Seven (c) Nine.
(In reply to re: Partial Solution
Yeah, I just caught that and was about to correct myself. :) It looks like you have the right idea.
As far as the divisibility by 7, I also think that it would be 1/7 and 6/7, respectively, but I'm not sure how to show that it is...
Posted by tomarken
on 2006-04-25 13:16:20