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Simple distances (Posted on 2006-05-01) Difficulty: 3 of 5
For this you will need four pennies. Arrange the pennies so that the centers of all four are equidistant from each other.

Example:

(1) (2) (3) (4)

This will not work because penny 1 and penny 4 are farther apart than penny 1 and penny 2.

See The Solution Submitted by Stephen    
Rating: 1.8571 (7 votes)

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re(3): Pennies of Giza | Comment 5 of 8 |
(In reply to re(2): Pennies of Giza by Vishal Gupta)

When we come to triangle-shaped pyramids, I see no problem at all, Vishal. What I pointed at was the definition of pyramid, as follows:

A solid figure with a polygonal base and triangular faces that meet at a common point.

And, as our best images of pyramids I imagine to be the ones of Egypt, here's the description of those:

A massive monument of ancient Egypt having a rectangular base and four triangular faces culminating in a single apex, built over or around a crypt or tomb.

So, as you see, the vocabule "pyramid" may mean a polyhydron with four vertices and faces, but not necessarily (and not commonly as well). As this word was potentially misleading to me, I thought it might have been the same to others and decided to give the polyhedron its rightful name to fit the problem's solving (in this stance, a tetrahedron). Like I said, all was probably a matter of speech, but in a hurry I might have mistaken Jyqm's idea.

Now that I think of it, it's not as important, other than giving the polyhedron Jyqm described its rightful name.


  Posted by Phil_Osopher on 2006-05-02 17:23:34
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