Find 2000 consecutive composite numbers.
(Of course you can't do this by trial and error alone)
For those who do not know what a composite number is, it is any integer greater than 1 that is not prime. (4, 6, 8, 9, ...)
(In reply to
solution by Charlie)
I'm not 100% sure on this, but here goes...
Given:
1. the logic already explained by Charlie and Ravi that produced the answer 2001!+2.......2001!+2001.
2. for every x in {1, 1000} there exists y in {1001,2001} such that y/x is an integer.
Therefore the series (2001!)/(1000!) + 2, .....(2001!)/(1000!) + 2001 should also be 2000 consecutive composite numbers.
There will also be an even smaller series found by breaking {1001, 2001} into it's prime factors and cancelling out where appropriate.
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Posted by fwaff
on 2003-03-06 22:10:14 |
Smaller solution?
