Find 2000 consecutive composite numbers.
(Of course you can't do this by trial and error alone)
For those who do not know what a composite number is, it is any integer greater than 1 that is not prime. (4, 6, 8, 9, ...)
I can't say I agree with you guys on this one. I'll justify my doubt with a smaller numbered version of your arguments.
In trying to find 5 consecutive composite numbers, you'd start with 5! (or 120). Then the reaasoning is that 5!, 5!+1, 5!+2, 5!+3 and 5!+4 are a string of composite numbers because 5! is dividsible by all of the addition parts. Well, 121 (while it is a composite of 11*11), isn't divisible by the first 5 numbers. Will this method then produce reliable results, or have I missed a part of your explanation?
not sure
