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Composite numbers (Posted on 2003-03-05) Difficulty: 3 of 5
Find 2000 consecutive composite numbers.

(Of course you can't do this by trial and error alone)

For those who do not know what a composite number is, it is any integer greater than 1 that is not prime. (4, 6, 8, 9, ...)

See The Solution Submitted by Anoop    
Rating: 3.7143 (7 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
just because ... | Comment 19 of 23 |
Since I like finding prime numbers so much, I figured I would give this one a shot since I finally made a program that could handle large numbers. I just wanted to find a value smaller than that given so far, and here it is:

2,107,757,298,379,527,717,213,600,518,699,389,595,229,783,738,061,356,212,322,972,511,214,654,115,727,593,174,080,683,423,236,414,793,504,734,471,782,400,000,000,000,000,542,683 is a 133-digit prime number, as is:

2,107,757,298,379,527,717,213,600,518,699,389,595,229,783,738,061,356,212,322,972,511,214,654,115,727,593,174,080,683,423,236,414,793,504,734,471,782,400,000,000,000,000,544,813

Between the two values we have 2,129 consecutive composite numbers. These two values are actually (87! + 542,683) and (87! + 544,813). While this is nowhere near the minimal solution, the problem caught my interest when I stumbled upon it, so I figured I'd see what I could do.

  Posted by Justin on 2010-08-01 11:04:37
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