All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
How many Integers? (Posted on 2006-05-18) Difficulty: 2 of 5
Find the number of positive integers that divide (10)^999 but not (10)^998.

No Solution Yet Submitted by Ravi Raja    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution solution | Comment 2 of 9 |

For a number to evenly divide the one but not by the other, it must be divisible by either 5^999 or by 2 ^ 999.  (Note, this includes the possibility it is divisible by both.)

So the numbers are of the form 5^999 * 2^n, where n is from zero to 999 inclusive, or 2^999 * 5 ^n, where n is from zero to 999 inclusive.  Each of these sets has 1000 members, but one of the members, 10^999 itself, is a member of both sets and has been counted twice, so the number sought is 1000+1000-1 = 1999.

Edited on May 18, 2006, 9:15 am
  Posted by Charlie on 2006-05-18 09:11:23

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information