I am a three digit number.
I am either divisible by 3 or by 5.
I am either divisible by 4 or by 6.
I am either divisible by 5 or by 7.
I am either divisible by 6 or by 8.
I am either divisible by 7 or by 9.
I am either divisible by 9 or by 11.
What am I?
(Note: "divisible" means leaving no remainder.)
(In reply to
The answer by Lincoln)
The problem with 810 is that it's divisible by both 3 and 5, while the supposed common understanding of either...or is to exclude the possibility of both parts being true.
If the possibility of an inclusive or is allowed, then all the following work:
126, 180, 252, 270, 360, 378, 450, 462, 504, 540, 630, 720, 756, 810, 882, 900, 924, 990

Posted by Charlie
on 20060515 16:07:43 