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 Arrange The Disks (Posted on 2006-07-04)
A set of 47 disks are consecutively numbered 1 to 47 and placed in a row as follows: 1, 2, 3, 4, ... 45, 46, 47.

Rearrange the disks so for any two given disks A and B, the disk equal to their arithmetic mean doesn't lie between them. For example, Disk 4 cannot lie between Disk 1 and Disk 7 since the arithmetic mean of 1 and 7 is 4. However, since 7 is not equal to the arithmetic mean of 1 and 4, Disk 7 may lie between Disk 1 and Disk 4.

 See The Solution Submitted by K Sengupta Rating: 3.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 re(2): solution (with solution/spoiler) | Comment 4 of 14 |
(In reply to re: solution (with solution/spoiler) by Dej Mar)

The following sets appear within Dej Mar's list of numbers, in the order shown, and have the mean lying between the two end numbers:

` 45  33  21 45  25  5 45  41  37 45  37  29 47  35  23 47  27  7 47  43  39 47  39  31 46  34  22 46  26  6 46  42  38 46  38  30`

 Posted by Charlie on 2006-07-04 22:00:56

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