All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
Cherry picking (Posted on 2006-06-17) Difficulty: 3 of 5
Out of a quite large set of random integer numbers, I selected only those that were multiples of M or N, and rejected the rest. In the resulting (obviously smaller) subset, 50% of the numbers were multiples of N. Curiously, M wasn't 50% of N.

What is the minimum possible pair of values for M and N? The next such pair? Are there infinite possible such pairs?

PS. If you don't know the reason for the "Cherry picking" title, check this reference or this other one.

PPS. And if "a quite large set" of numbers doesn't satisfy you, imagine an infinite set, with every possible integer.

See The Solution Submitted by Federico Kereki    
Rating: 4.7500 (4 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution Answer | Comment 3 of 4 |
Let's say GCD(M,N)=L; then, M=Lm and N=Ln, with GCD(m,n)=1. Also, LCM(M,N)=Lmn. Out of the numbers from 1 to Lmn, n are multiples of Lm (=M) and m are multiples of Ln (=N). However, the total number of multiples is m+n-1 because the number Lmn itself is counted twice. We are told that n/(m+n-1)=1/2, so n=m-1.

The minimum answer is found for L=1, n=2 (N=1 isn't allowed) and m=3.

The general answer is (Ln,L(n+1)) for integer L and n.

  Posted by e.g. on 2006-06-17 22:09:05
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (21)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information