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 Gardener's Woe (Posted on 2006-06-24)
An unlucky gardener planted a 10x10 square array of 100 old seeds out in the garden. Only 5 of these seeds have germinated including one at the southwest corner (0,0) where a slug is currently reducing it to ground level.

When it finishes it will head directly to the next closest doomed plant. After it eats that one it will again leave a slime trail to the closest remaining plant and so on until the garden is no more.

Where are the 4 remaining seedlings if the path crawled by the slug is the longest possible and it never has to choose between two equidistant snacks?

Note: Although the slug will never have to choose between two equidistant seedlings, this doesn't imply that no two are equidistant.

Next find the locations if 6 seedlings had germinated instead of 5.

 See The Solution Submitted by Jer Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 My solution for 5 seeds | Comment 13 of 26 |
Starting from 0,0 and going to 7,7 then 10,10. Now the slug has 2 possibilities to go either 0,10 or 10,0 and after choosing from those it crosses the field to get to either 0,10 or 10,0. Either way the distance would be 10(1+2√2) which is about 38,28 units
 Posted by atheron on 2006-06-25 10:54:47

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