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Six Tenants Problem (Posted on 2006-08-25) Difficulty: 3 of 5
A group of six people live in the same apartment building. On a particular occasion, they got together one day for lunch. As part of their conversation, they discovered that each one lived on a different floor and that the amount of rent paid by each one of them was all different. Two facts immediately emerged out of the luncheon meeting. The higher the floor , the higher was the rent. The rent paid by one of the six people was $525.

The details of the six people are furnished below ( albeit not necessarily in that order).

First Names: Alice, Paul, Denise, Fiona, Sandra, Joe.

Last Names: Ackers, Pryor, Davidson, Johnson, Stevens, Falkin.

Floor: 12th, 14th, 17th, 21st, 24th, 25th.

Using the clues given below, determine the full names of the six renters, the floor on which each resides, and the amount of rent they each pay.

1. Ms. Johnson lives between Denise and Ackers.

2. The highest rent is not paid by Falkin, Stevens or Paul. It is $175 more than that of the 17th floor.

3. Floor 21 is rented at $75 more than where Ackers lives and $50 less than what Alice pays.

4. Sandra pays $475 which is $175 less than Ms. Davidson.

5. Pryorís rent is $50 higher than Aliceís rent and $100 more than the rent paid by Joe.

6. The rent at the 12th floor is $450. No one with the initial P or A ( in either their first names or their surnames) lives there.

7. Stevensí rent is lower than Johnsonís.

See The Solution Submitted by K Sengupta    
Rating: 4.2500 (8 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Solution or Multiple solution | Comment 6 of 21 |
(In reply to re: Solution or Multiple solution by Salil)

Okay Sorry I missed the gender. There is only one solution.
  Posted by Salil on 2006-08-25 12:30:02

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