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Calling all pythagoreans (Posted on 2006-07-03) Difficulty: 3 of 5
The triangle with sides 3, 4, and 5, is the smallest integer sided pythagorean triangle. Can you prove that in every such triangle:
  • at least one of its sides must be multiple of 3?
  • at least one of its sides must be multiple of 4?
  • at least one of its sides must be multiple of 5?

See The Solution Submitted by e.g.    
Rating: 5.0000 (1 votes)

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Somekind of solution | Comment 3 of 7 |
All pythagorean triples can be generated with formula 2MN,M^2-N^2,M^2+N^2 where M and N are relatively primes and M>N
It's pretty easy to see that every one of those three is divisible by either 3,4 or 5 depending on wether M and/or N are odd or even numbers (Can be proved easily with induction)
Since all of them are divisible by 3,4 or 5 every such triangle must have sides in the way described in this problem.
More on MathWorld..

Edited on July 3, 2006, 1:57 pm
  Posted by atheron on 2006-07-03 13:56:09

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