You have six balls - three red and three black. All the red balls weigh differently, i.e. one of them is heavy, the other medium, and the third light. Each red ball has a black twin of the same weight. A heavy and a light ball put together weigh as much as two medium balls.
What is the least number of weighings required on a balancing scale to determine which is which?
(In reply to Less trivial boundary
by Steve Herman)
I agree that you can sort the red and black balls in five weighings.
But, as yet, I also have not concluded that five is the minimum.
Posted by Dej Mar
on 2006-07-07 16:06:41