You have six balls  three red and three black. All the red balls weigh differently, i.e. one of them is heavy, the other medium, and the third light. Each red ball has a black twin of the same weight. A heavy and a light ball put together weigh as much as two medium balls.
What is the least number of weighings required on a balancing scale to determine which is which?
As there are 36 possible orderings (6 of red x 6 of black), limit would be ceil (log(36)/log(3)) = ceil(
3.26185951)=4 but that might not be actually achievable.

Posted by Charlie
on 20060709 13:47:35 