Consider laying out 10 sets of 4 cards plus a turn-up, from a single deck of cards, forming what might appear to be 10 cribbage hands including a different turn-up for each. (Two cards will be left over.)
How could these sets be arranged to maximize the sum of the scores of these hands?
http://en.wikipedia.org/wiki/Cribbage may provide you with some guidance.
Note: Each hand has its own turn-card so a single jack in each hand could be the right jack.
(In reply to Did I just peg out?
by Dej Mar)
Well its higher that my best of 196. I thought it was best to have lots of runs. Apparently its better to have lots of four of a kinds. When I post the 'official' solution, I'll include both.
Posted by Jer
on 2006-07-19 09:20:56