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10 Ultimate cribbage hands (Posted on 2006-07-18) Difficulty: 4 of 5
Consider laying out 10 sets of 4 cards plus a turn-up, from a single deck of cards, forming what might appear to be 10 cribbage hands including a different turn-up for each. (Two cards will be left over.)

How could these sets be arranged to maximize the sum of the scores of these hands?

http://en.wikipedia.org/wiki/Cribbage may provide you with some guidance.
Note: Each hand has its own turn-card so a single jack in each hand could be the right jack.

  Submitted by Jer    
Rating: 3.3333 (3 votes)
Solution: (Hide)
DejMar pegs 205, mostly by getting lots of four-of-a-kinds with the face cards:
A, A, 2, 2, 3 = 16
A, A, 2, 2, 3 = 16
4, 4, 4, 4, 3 = 20
6, 6, 6, 6, 3 = 24
7, 7, 8, 8, 9 = 24
7, 7, 8, 8, 9 = 24
10,10,10,10, 5 = 20
J, J, J, J, 5 = 21
Q, Q, Q, Q, 5 = 20
K, K, K, K, 5 = 20
===================
Total 205

The two cards left over are two 9s.


My best was 196, concentrating on 16-point-runs:
AA223 x2 = 16x2
44556 x2 = 24x2
67788 x2 = 24x2
99TTJ x2 = 17x2 with the right jack
JQQKK x2 = 17x2 with the right jack
[The extra cards here are a pair of 3's but could have been A, 2 or 3 or even a combination.]

Comments: ( You must be logged in to post comments.)
  Subject Author Date
Puzzle ThoughtsK Sengupta2023-05-08 23:03:47
Nice oneCharlotte2021-11-16 10:03:50
re: Did I just peg out?Jer2006-07-19 09:20:56
re(2): Did I just peg out?Dej Mar2006-07-18 20:58:48
re: Did I just peg out?Steve Herman2006-07-18 20:46:15
SolutionDid I just peg out?Dej Mar2006-07-18 19:43:42
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