(2^(31)1)/3 = 1
(2^(71)1)/7 = 9
with no other solutions through m=8563, where overflow took place in:
10 while m<1000000
20 m=nxtprm(m)
30 n=(2^(m1)1)/m
40 if n=int(n) then
50 :s=int(sqrt(n))
60 :if s*s=n then ? m,n
70 wend

Posted by Charlie
on 20060923 16:05:01 