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 Find the J (Posted on 2006-08-04)
Each letter of the alphabet has been assigned a different value from 1 to 26. The number following each word is the sum of all the letters in it. Your task is to discover the values of all the letters and then decide the value of J, which is not used.
```ABLE  38   ACID  23   ACRID 24   ADMIT  45
ALE   30   ANIL  48   ANKLE 66   ANTLER 52
ANVIL 66   APPLE 72   AQUA  36   AREA   12
ARENA 24   ARROW 27   AURA  27   AWAY   41
AWE   24   AWFUL 78   AXLE  44   AZALEA 49
```

 See The Solution Submitted by Josie Faulkner Rating: 4.4000 (15 votes)

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 solution | Comment 3 of 25 |

The first few I found were R=1, N=12, B=8, Q=10, X=14, V=18, P=21, K=24, T=9.

Then, because 2A+E = 11 (from AREA and R=1), and other similar relationships, these were the  possibilities:

` A  E  Z  Y  U 2  7 15 22 22 3  5 13 19 20 4  3 11 16 18`

But the first line has two 22's and the last line assigns 18 to U, but 18 is already assigned to V.  That makes A=3, E=5, Z=13, Y=19, U=20.

Then further algebra among the words leads to W=16, L=22, I=11, G=23.

Then, for D, O and C, using only unused possibilities for D:

` D  O  C 6  7  3 7  6  2`

But 3 is already used by A, so D=7, O=6 and C=2.

From there it was straight algebra again, with H=25, F=17, M=15 and S=4.  That leaves 26 for J.

 Posted by Charlie on 2006-08-04 14:49:24

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