Each letter of the alphabet has been assigned a different value from 1 to 26. The number following each word is the sum of all the letters in it. Your task is to discover the values of all the letters and then decide the value of J, which is not used.

ABLE 38 ACID 23 ACRID 24 ADMIT 45
ADO 16 AGREE 37 AHEAD 43 AISLE 45
ALE 30 ANIL 48 ANKLE 66 ANTLER 52
ANVIL 66 APPLE 72 AQUA 36 AREA 12
ARENA 24 ARROW 27 AURA 27 AWAY 41
AWE 24 AWFUL 78 AXLE 44 AZALEA 49

(In reply to

Try by CMAS23)

From AREA and AURA, 2A + E = 11 and 2A + U = 26

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So

A E U

2 7 22

3 5 20

4 3 18

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It can’t be the third option because V is 18.

If A is 2 and E is 7 then L is 21. (ALE)

This can’t be right because P is 21 (APPLE)

So A is 3 and E is 5. (This makes W 16.)

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