Here is a 8X8 square containing numbers 1 to 5 repeated four times. Can you divide the square into four similar shaped pieces such that each piece contains only one set of five numbers?

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| 1 | | | | | | | 1 |
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| 4 | 3 | | | 4 | | | |
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| | | | | 5 | | | 2 |
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| | | | | 5 | | | 2 |
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| 3 | | | 5 | 5 | | | |
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| | | | 3 | | | | |
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| 4 | | 2 | 2 | | | | |
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| 1 | | | | | 3 | 4 | 1 |
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My solution. I know it's a repeat of brianjn's and Dej Mar's, but since I went to all the work of finding it, I couldn't resist posting.

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| 1 | 1 |

| --------- --------- |

| 4 | 3 4 | | |

| | | | |

| | 5 | | 2 |

| --------- ----- ----|

| | | 5 2 |

| --------- |

| 3 5 | 5 | |

|---- ----- --------| |

| | | 3 | |

| | | | |

| 4 | 2 | 2 | |

| --------- --------- |

| 1 | 3 4 1 |

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I had an interesting hypothesis which turned out to be true. Looking at the 5s near the middle, I knew they had to be divided, making part of a cross. I completed that cross and guessed that the pieces would form rotational symmetry around the center. So, I just replicated every cut that I knew I needed 3 more times around the center, and the solution quickly emerged.