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 Five Circle Division (Posted on 2006-08-26)
Five circles are arranged in the following fashion ( Two rows of 3 circles in square arrangement with one end circle removed from the top row ). Circles are of same diameter and touching adjoining circles as per the diagram. Draw a line passing through A ( Centre of the first circle on the bottom row ) in such a way that it divides the five circles into two equal areas.

```
*                 *
*         *       *         *
*             *   *             *
*               * *               *
*                 *                 *
*               * *               *
*             *   *             *
*         *       *         *
*                 *                 *
*         *       *         *       *         *
*             *   *             *   *             *
*               * *               * *               *
*        A        *                 *                 *
*               * *               * *               *
*             *   *             *   *             *
*         *       *         *       *         *
*                 *                 *

```

 No Solution Yet Submitted by Salil No Rating

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 Spoiler | Comment 1 of 15
If a figure has a center of symmetry, any line through it will divide it in two equal parts.

A is the center of symmetry for the circle on the left.

The four circles on the right have a center of symmetry B: it's the center of the inner rhombus they form.

So, just join A with B and you are done.
 Posted by e.g. on 2006-08-26 10:52:10

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