Five circles are arranged in the following fashion ( Two rows of 3 circles in square arrangement with one end circle removed from the top row ). Circles are of same diameter and touching adjoining circles as per the diagram. Draw a line passing through A ( Centre of the first circle on the bottom row ) in such a way that it divides the five circles into two equal areas.
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If a figure has a center of symmetry, any line through it will divide it in two equal parts.
A is the center of symmetry for the circle on the left.
The four circles on the right have a center of symmetry B: it's the center of the inner rhombus they form.
So, just join A with B and you are done.

Posted by e.g.
on 20060826 10:52:10 