Five circles are arranged in the following fashion ( Two rows of 3 circles in square arrangement with one end circle removed from the top row ). Circles are of same diameter and touching adjoining circles as per the diagram. Draw a line passing through A ( Centre of the first circle on the bottom row ) in such a way that it divides the five circles into two equal areas.
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(In reply to
re: Equation spoiler by Richard)
>
Your equation looks to be correct if the circles have radius 1
?? It is correct anyway; scaling the circles does not change the equation for the line if A remains the origin. The scale applies to both x and y and cancels out in the slope; otherwise we'd get ellipses.

Posted by vswitchs
on 20060826 12:34:39 