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 Five Circle Division (Posted on 2006-08-26)
Five circles are arranged in the following fashion ( Two rows of 3 circles in square arrangement with one end circle removed from the top row ). Circles are of same diameter and touching adjoining circles as per the diagram. Draw a line passing through A ( Centre of the first circle on the bottom row ) in such a way that it divides the five circles into two equal areas.

```
*                 *
*         *       *         *
*             *   *             *
*               * *               *
*                 *                 *
*               * *               *
*             *   *             *
*         *       *         *
*                 *                 *
*         *       *         *       *         *
*             *   *             *   *             *
*               * *               * *               *
*        A        *                 *                 *
*               * *               * *               *
*             *   *             *   *             *
*         *       *         *       *         *
*                 *                 *

```

 No Solution Yet Submitted by Salil No Rating

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 solution | Comment 5 of 15 |
Let B and C be the centers of the next two circles in the bottom row and D and E the centers of the two circles in the above row. Let M be the intersection between DC and BE. M is the simetry point of the figure formed by the four circles (of centers B, C, D, E) and the zone between them, and A is the simetry point of the first circle in the bottom row. So, the line AM divides the five circles into two equal areas.
 Posted by Stefan on 2006-08-26 12:55:56

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