Change the position of only one number in the sequence given below in order that the amended sequence corresponds to a palindromic sequence.
1, 4, 9, 6, 2, 1, 5, 10, 4
*** Source: Adapted from a problem which appeared in Mensa Canada Website.
Either the first number 1 or 2 shifted to the last position, with each number converted to Roman numerals, will result in a palindromic sequence (ignoring commas and spaces):
IV, IX, VI, II, I, V, X, IV, I --> IVIXVIIIIVXIVI
or,
I, IV, IX, VI, I, V, X, IV, II --> IIVIXVIIVXIVII
or,
using the additive notation for Roman numeral 4 (IIII),
IIII, IX, VI, II, I, V, X, IIII, I --> IIIIIXVIIIIVXIIIII
or,
using the additive notation for Roman numeral 4 (IIII),
I, IIII, IX, VI, I, V, X, IIII, II --> IIIIIIXVIIVXIIIIII
Converting all but the numeral 2 into Roman numerals with, optionally, converting the 2 into its equivalent in most any other numeral system, after shifting the initial 1 to the final position, will also work:
IV, IX, VI, 2, I, V, X, IV, I --> IVIXVI2IVXIVI
or,
using the additive notation for Roman numeral 4 (IIII),
IIII, IX, VI, 2, I, V, X, IIII, I --> IIIIIXVI2IVXIIIII
Edited on October 10, 2008, 11:56 am
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Posted by Dej Mar
on 2008-10-10 10:12:34 |