The number 201 is divided by a positive integer N. It is observed that the quotient, remainder and divisor (that is, N itself), but not necessarily in this order, are in geometric sequence.
What can N be?
(In reply to
doing something wrong? by Jer)
I had the same idea and also couldn't find a solution... I worked on it so long that my brain started to fry and for a full minute I thought I had found a solution where N = 42, Q = 12, and R = 147. Obviously that is not correct, so I gave up! :)

Posted by tomarken
on 20061109 11:20:59 