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Geometric Integers (Posted on 2006-11-09) Difficulty: 2 of 5
The number 201 is divided by a positive integer N. It is observed that the quotient, remainder and divisor (that is, N itself), but not necessarily in this order, are in geometric sequence.

What can N be?

See The Solution Submitted by K Sengupta    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: doing something wrong? | Comment 5 of 6 |
(In reply to doing something wrong? by Jer)

What a silly mistake!
After coming up with

q(qx + x^2) = 201

I went on to assume that (qx + x^2) had to be an integer.  This would imply that q divides 201 which it clearly cannot.

  Posted by Jer on 2006-11-10 14:31:11
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