Consider six consecutive positive integers. Show that there is a prime number that divides exactly one of them.
(In reply to
Proof by Tristan)
It's not quite true that exactly 5 of the numbers are divisble by 2, 3,
or 5. It is possible that 2 of the numbers can be divisible by none of
2, 3, or 5: for example (15, 16, 17, 18, 19, 20) has 2 numbers that are
primes bigger than 5.
I don't think this really affects your proof, however, because what
seems to be important is that at least one of the numbers is not
divisible by 2, 3, or 5, and that is true.
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Posted by Richard
on 2006-08-29 19:29:21 |
re: Proof
