Another function problem (Posted on 2006-11-19)

	Submitted by K Sengupta
Rating: 4.0000 (1 votes)
Solution:	(Hide)
At the outset, we note that x = 4 is a solution of f1(x)= 2x Hence, f2(x) = x2+6f1(x)= 2x, also has a solution x =4 Accordingly, by induction it can be shown that if fn(x) = 2x has a solution x=4, so does the equation fn+1(x)( i.e. possesses a solution of x=4 By induction, it also follows that fn(x)/x decreases as x increases for every n. Consequently, fn(x)= 2x possesses the unique solution x=4 **************************************** In addition, refer to the explanation provided by Paul in this location. Joel also provides a good methodology here.

	Subject	Author	Date
	re(2): Solution?	Joel	2006-11-21 23:22:33
	Solution	Rajesh	2006-11-21 13:17:42
	a complete solution	Paul	2006-11-20 10:07:25
	re(8): Solution?	tomarken	2006-11-20 01:26:34
	re(7): Solution?	Richard	2006-11-19 20:40:39
	re(6): Solution?	tomarken	2006-11-19 19:45:48
	re(5): Solution?	Richard	2006-11-19 18:02:36
	re(4): Solution?	tomarken	2006-11-19 16:04:04
	re(3): Solution?	Richard	2006-11-19 12:40:29
	re(2): Solution?	tomarken	2006-11-19 12:14:56
	re: Solution?	Richard	2006-11-19 12:01:06
	Solution?	tomarken	2006-11-19 11:17:32